Turn A Single Number Into Single Digits Python

I want to make a number , for example 43365644 into single numbers [4,3,3....,4,4] and append it on a list

Solution 1:

Here's a way to do it without turning it into a string first (based on some rudimentary benchmarking, this is about twice as fast as stringifying n first):

>>> n = 43365644
>>> [(n//(10**i))%10 for i in range(math.ceil(math.log(n, 10))-1, -1, -1)]
[4, 3, 3, 6, 5, 6, 4, 4]

Updating this after many years in response to comments of this not working for powers of 10:

[(n//(10**i))%10 for i in range(math.ceil(math.log(n, 10)), -1, -1)][bool(math.log(n,10)%1):]

The issue is that with powers of 10 (and ONLY with these), an extra step is required. ---So we use the remainder in the log_10 to determine whether to remove the leading 0--- We can't exactly use this because floating-point math errors cause this to fail for some powers of 10. So I've decided to cross the unholy river into sin and call upon regex.

In [32]: n = 43

In [33]: [(n//(10**i))%10 for i in range(math.ceil(math.log(n, 10)), -1, -1)][not(re.match('10*', str(n))):]
Out[33]: [4, 3]

In [34]: n = 1000

In [35]: [(n//(10**i))%10 for i in range(math.ceil(math.log(n, 10)), -1, -1)][not(re.match('10*', str(n))):]
Out[35]: [1, 0, 0, 0]

Solution 2:

The easiest way is to turn the int into a string and take each character of the string as an element of your list:

>>> n = 43365644 
>>> digits = [int(x) for x in str(n)]
>>> digits
[4, 3, 3, 6, 5, 6, 4, 4]
>>> lst.extend(digits)  # use the extends method if you want to add the list to another

It involves a casting operation, but it's readable and acceptable if you don't need extreme performance.

Solution 3:

If you want to change your number into a list of those numbers, I would first cast it to a string, then casting it to a list will naturally break on each character:

[int(x) for x in str(n)]