Python - Deleting The First 2 Lines Of A String
Solution 1:
I don't know what your end character is, but what about something like
postString = inputString.split("\n",2)[2]
The end character might need to be escaped, but that is what I would start with.
Solution 2:
x="""version 1.00
6992
[-4.32063, -9.1198, -106.59][0.00064, 0.99993, -0.01210][etc...]
abc
asdda"""print"\n".join(x.split("\n")[2:])
You can simply do this.
Solution 3:
Remove the lines with split
:
lines = """version 1.00
6992
[-4.32063, -9.1198, -106.59][0.00064, 0.99993, -0.01210][etc...]"""lines = lines.split('\n',2)[-1]
Solution 4:
''.join(x.splitlines(keepends=True)[2:])
splitlines
produces a list of strings. If keepends=True
is given, line breaks are included in the resulting list l
and ''.join(l)
can be used to reproduce the original string.
Note that splitlines
works well with a number of different line boundaries such as \u2028
>>>x = 'a\u2028b\u2028c\u2028'>>>''.join(x.splitlines(keepends=True)[2:])
'c\u2028'
while split('\n')
fails in this case:
>>> x ='a\u2028b\u2028c\u2028'>>> x.split('\n',2)[2]
Traceback (most recent calllast):
File "<stdin>", line 1, in<module>
IndexError: list index outofrange
Also note that splitlines
and split('\n')
behave differently if they are called on an empty string or a string that ends with a newline character. Compare the following examples (copied from the documentation of splitlines
):
>>> "".splitlines()
[]
>>> "One line\n".splitlines()
['One line']
>>> ''.split('\n')
['']
>>> 'Two lines\n'.split('\n')
['Two lines', '']
However, if keepends=True
is given, the trailing newline is preserved:
>>> "One line\n".splitlines(keepends=True)
['One line\n']
More examples and a list of what splitlines
treats as a line boundary can be found here:
https://docs.python.org/3/library/stdtypes.html?highlight=split#str.splitlines
Solution 5:
You could use some rules, like consider those lines only if they start with '['
character lines = [line for line in lines if line.startswith('[')]
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