How Do I Skip A Few Iterations In A For Loop
Solution 1:
You cannot alter the target list (i
in this case) of a for
loop. Use a while
loop instead:
while i < 10:
i += 1ifi== 2:
i += 3
Alternatively, use an iterable and increment that:
from itertools import islice
numbers = iter(range(10))
for i in numbers:
if i == 2:
next(islice(numbers, 3, 3), None) # consume 3
By assigning the result of iter()
to a local variable, we can advance the loop sequence inside the loop using standard iteration tools (next()
, or here, a shortened version of the itertools
consume recipe). for
normally calls iter()
for us when looping over a iterator.
Solution 2:
The best way is to assign the iterator a name - it is common have an iterable as opposed to an iterator (the difference being an iterable - for example a list - starts from the beginning each time you iterate over it). In this case, just use the iter()
built-in function:
numbers = iter(range(100))
Then you can advance it inside the loop using the name. The best way to do this is with the itertools
consume()
recipe - as it is fast (it uses itertools
functions to ensure the iteration happens in low-level code, making the process of consuming the values very fast, and avoids using up memory by storing the consumed values):
from itertools import islice
import collections
defconsume(iterator, n):
"Advance the iterator n-steps ahead. If n is none, consume entirely."# Use functions that consume iterators at C speed.if n isNone:
# feed the entire iterator into a zero-length deque
collections.deque(iterator, maxlen=0)
else:
# advance to the empty slice starting at position nnext(islice(iterator, n, n), None)
By doing this, you can do something like:
numbers = iter(range(100))
for i in numbers:
...
if some_check(i):
consume(numbers, 3) # Skip 3 ahead.
Solution 3:
Why not just set the value to skip until? Like:
skip_until = 0for i inrange(100):
if i < skip_until:
continueif SOME_CONDITION:
skip_until = i + 10
DO_SOMETHING()
where SOME_CONDITION is whatever causes you to skip and DO_SOMETHING() is the actual loop contents?
Solution 4:
for i in range(0, 100, 10):
print(i)
will print 0, 10, 20 ...
Solution 5:
A charmed and simplest form is like that:
>>>for i inrange(5,10):...print (i)...
5
6
7
8
9
Where 5
was the index that started iteration.
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