Django - Prepare Objects From A View For Current User

Consider this model class Exercise(models.Model): name = models.CharField(max_length=50) def __unicode__(self): return self.name class Score(models.Model): '''Scores of

Solution 1:

What I'd do would be to get all the user's current scores up front, create a dictionary mapping exercise to score, then add the score as an attribute of each exercise. Something like:

user_scores = request.user.score_set.all()
score_dict = dict((sc.exo_id, sc.score) for sc in user_scores)
exos = Exercise.objects.all()
for ex in exos:
    ex.current_user_score = score_dict.get(ex.id)

Now each exercise in exos has a current_user_score attribute, which is the current user's score for that exercise (or None).

Solution 2:

django.contrib.auth has a context processor that adds a user variable to the template context, referencing the current user. This can enable you to get all scores for the current user, then you can create a template filter that returns the score for a particular exercise.

In a file named exercises.py within a templatetags package.

[Put the package in the folder of one of your apps in INSTALLED_APPS. Remember templatetags must be a valid Python package ie. with an __init__.py]

from django.template import Library
register = Library()

@register.filterdefscore_for_exercise(scores, exercise):
    s = scores.filter(exo=exercise)
    if s:
        return s[0].score
    returnNone

In the template:

{% load exercises %}
{% with user.score_set.all as user_scores %}
<ul>
  {% for exo in exos %}
    {% with user_scores|score_for_exercise:exo as score %}
    <li>{{ exo }}{% if score %} - {{score}}{% endif %}</li>
    {% endwith %}
  {% endfor %}
</ul>
{% endwith %}

Solution 3:

Maybe you can add an attribute to your Exercise:

classExercise(models.Model):
    name = models.CharField(max_length=50)

    def__unicode__(self):
        returnself.name

    defuser_score(self):
        return Score.objects.get(exo=self).score