Need To Derive A Function For Palindrome

I need to derive a function which takes a string and returns whether or not that string is a palindrome and my function should return True on strings which are palindromes if space

Solution 1:

>>>text = 'a man a plan a canal panama'>>>x = ''.join(text.split())>>>x == x[::-1]
True

Solution 2:

Outline

A phrase is a palindrome if the i'th character is the same as the len-i'th character. Since the series is a mirror image, you haveto go only as far as the middle.

To get the effect you are looking for,you can normalize on whitespace, punctuation, and string case before calculating whether a string is a palindrome or not..

Code

from string import punctuation

defis_palindrome(s):
    returnall(s[i] == s[-(i + 1)] for i inrange(len(s)//2))

defnormalized_palindrome(s):
    return is_palindrome("".join(c for c in s.replace(" ","").lower() if c notin punctuation))

You can also use zip and reversed to iterate pairwise over letters:

defis_palindrome(s):
    returnall(a == b for a, b inzip(s, reversed(s)))

Of course, that does not stop in the middle.

Test

>>>tests = [..."able was I ere I saw Elba",..."a man, a plan, a canal: Panama!",..."Was it Eliot's toilet I saw?",...]>>>>>>for test in tests:...print normalized_palindrome(test)... 
True
True
True

Your code

As for your original, it's correct by me:

>>>s = "able was I ere I saw Elba".lower()>>>defispalindrome(word):...iflen(word) < 2: returnTrue...if word[0] != word[-1]: returnFalse...return ispalindrome(word[1:-1])...>>>ispalindrome(s)
True
>>>s = "a man a plan a canal panama">>>ispalindrome(s)
False
>>>ispalindrome(s.replace(" ",""))
True

Solution 3:

You can store the string that is free of special characters and spaces and then check if it is a palindrome or not.

defisPalindrome(s: str) -> bool:
    mystring = s.lower()
    mystring2 = ""for i inmystring:if i.isalnum():
            mystring2 += i

    return (mystring2 == mystring2[::-1])